Moonshot’s K3 may be far costlier to serve past 100K tokens than V4
teortaxesTex · x · 2026-07-21
The reply argues that K3 may be modestly to massively more expensive to serve than V4 above 100K tokens, depending on the assumptions. If Moonshot has unusually dense compute, that cost may still be acceptable.
It also notes the upside: K3 is a frontier model, so its architecture may justify the serving tradeoff if the quality gains are strong enough.
Related event: Debate Over Moonshot K3 Deployment and Inference Costs(2 posts)→
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